In the diagram as shown, a circle is drawn with centre `C(1,1)` and radius 1 and a line L. The line L is tangent to the circle at Q. Further L meets the y-axis at R and the x-axis at P in such a way that the angle OPQ equals `theta` where `0 lt theta lt (pi)/(2)`.
Equation of the line PR is

In the diagram as shown, a circle is drawn with centre C(1,1) and radius 1 and a line L. The line L is tangent to the circle at Q. Further L meets the y-axis at R and the x-axis at P in such a way that the angle OPQ equals theta where 0 lt theta lt (pi)/(2) . Coordinate of Q is

In the diagram as shown, a circle is drawn with centre C(1,1) and radius 1 and a line L. The line L is tangent to the circle at Q. Further L meets the y-axis at R and the x-axis at P in such a way that the angle OPQ equals theta where 0 lt theta lt (pi)/(2) . Area of triangle OPR when theta = pi//4 is

In the diagram as shown, a circle is drawn with centre C(1, 1) and radius I and a line L. The line Lis tangential to the circle at Q. Further L meet the y-axis at R and the x-axis at Pis such a way that the angle OPQ equals theta where 0 < theta

A tangent to the hyperbola (x^(2))/( 4) -(y^(2))/( 2) =1 meets x-axis at P and y-axis at Q . Lines PR and QR are drawn such that OPRQ is a rectangle (where O is the origin ) then R lies on

Tangents drawn to circle (x-1)^2 +(y -1)^2= 5 at point P meets the line 2x +y+ 6= 0 at Q on the x axis. Length PQ is equal to

The line 2x+3y=6, 2x+3y-8 cut the X-axis at A,B respectively. A line L=0 drawn through the point (2,2) meets the X-axis at C in such a way that abscissa of A,B,C are in arithmetic Progression. then the equation of the line L is