The value of `d/dx (log_2 log_3 x)` at `x = 3` is `(lnx = log_e x)`

(d)/(dx)(log e^(x)*log x)

d/(dx)log_|x|e=

d/(dx)log_|x|e=

d/dx (log_a x) =............ .

d/(dx)e^(log sqrt(x)}=

The function f(x)=e^x+x , being differentiable and one-to-one, has a differentiable inverse f^(-1)(x)dot The value of d/(dx)(f^(-1)) at the point f(log2) is 1/(1n2) (b) 1/3 (c) 1/4 (d) none of these

The function f(x)=e^x+x , being differentiable and one-to-one, has a differentiable inverse f^(-1)(x)dot The value of d/(dx)(f^(-1)) at the point f(log2) is 1/(1n2) (b) 1/3 (c) 1/4 (d) none of these

The function f(x)=e^x+x , being differentiable and one-to-one, has a differentiable inverse f^(-1)(x)dot The value of d/(dx)(f^(-1)) at the point f(log2) is 1/(1n2) (b) 1/3 (c) 1/4 (d) none of these

The function f(x)=e^(x)+x, being differentiable and one-to-one,has a differentiable inverse f^(-1)(x) .The value of (d)/(dx)(f^(-1)) at the point f(log2) is (a) (1)/(1n2) (b) (1)/(3)( c) (1)/(4) (d) none of these

The function f(x)=e^x+x , being differentiable and one-to-one, has a differentiable inverse f^(-1)(x)dot The value of d/(dx)(f^(-1)) at the point f(log2) is (a) 1/(1n2) (b) 1/3 (c) 1/4 (d) none of these