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For what values of natural number n, 4^(...

For what values of natural number n, `4^(n)` can end with the digit 6?

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Prove that there is no natural number for which 4^(n) ends with the digit zero.

Prove that there is no natural number for which 4^n ends with the digit zero.

Consider the numbers 4^(n) , where n is a natural number. Check whether there is any value of n for which 4^(n) ends with the digit zero.

Consider the numbers 4^(n) , where n is a natural number. Check whether there is any value of n for which 4^(n) ends with the digit zero.

Show that any number of the form 4^(n),n ne N can never end with the digit 0.

Assertion (A): 6^(n) ends with the digit zero where n is a natural number. Reason (R):Any number ends with digit zero, if its prime factor is of the form 2^(m)xx5^(n) , where m,n are natural numbers.

Can the number 6^n , n being a natural number, end with the digit 5? Give reason.

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