`bar(AB)=3hati+hatj-hatk and bar(AC)=hati-hatk+3hatk.` If the point P on the line segment BC is equidistant from `AB and AC,` then `bar(AP)` is

bar(AB)=3hat i+hat j-hat k and bar(AC)=hat i-hat k+3hat k. If the point P on the line segment BC is equidistant from AB and AC, then bar(AP) is

Let vecAB = 3 hati + hatj - hatk and vecAC = hati -hatj + 3hatk and a point P on the line segment BC is equidistant from AB and AC, then vec (AP) is

Let vecAB = 3 hati + hatj - hatk and vecAC = hati -hatj + 3hatk and a point P on the line segment BC is equidistant from AB and AC, then vec (AP) is

The vector bar(AB)=3hati+4hatk and bar(AC)=5hati-2hatj+4hatk are the sides of a triangle ABC. The length of the median through A is

If bar A= 2hati+8hatj+7hatk and bar B=3hati+2hatj then the component of (barA+barB) along x-axis is

IF ABCD is a parallelogram, bar(AB)=2hati+4hatj-5hatk and bar(AD)=hati+2hatj+3hatk ,then the unit vector In the direction of BD Is

If hati+hatj+hatk, 2 hati+5 hatj, 3 hati+2 hatj-3 hatk and hati-6 hatj-hatk are the position vectors of points A, B , C and D respectively, then find the angle between bar(AB) and bar(CD) . Deduce that bar(AB) and bar(CD) are collinear.

bar(a)=hati+hatj+hatk,bar(b)=hati+3hatj+5hatk and bar( c )=7hati+9hatj+11hatk are vectors. The area of the parallelogram whose diagonals are bar(a)+bar(b) and bar(b)+bar( c ) is …………..

In DeltaABC,vec(AB)=3hati+4hatk and vec(AC)=5hati-2hatj+4hatk . Length of the median drawn from A is ………………