Find the value of tension in string 1 if the system equilibrium ? (g=10 `m//s^(2)`)

In the arrangement shown in the figure-2.188 if system is in equilibrium (g=10 m//s^(2))

A 1kg stone at the end of 1m long string is whirled in a vertical circle at a constant speed of 4m//s . The tension in the string is 6N , when the stone is at (g=10m//s^(2))

A 1kg stone at the end of 1m long string is whirled in a vertical circle at a constant speed of 4m//s . The tension in the string is 6N , when the stone is at (g=10m//s^(2))

Two blocks with masses m_(1) = 0.2 kg and m_(2) = 0.3 kg hang one under other as shown in figure. Find the tensions in the strings (massless) in the following situations : (g = 10 m//s^(2)) if maximum allowable tension is 10 N. What is maximum possible upward acceleration ?

A mass of 5 kg is tied to a string of length 1.0 m is rotated in vertical circle with a uniform speed of 4 m//s . The tension in the string will be 170 N when the mass is at (g=10 m//s^(2))

Inside a horizontally moving box, an experimenter finds that when an object is placed on a smooth horizontal plane and is released, it moves with an acceleration of 10 m//s^2 . In this box if 1 kg body is suspended with a light string, find the tension in the string in equilibrium position (w.r.t experimenter) (g = 10m//s^2 )

A mass of 2 kg tied to a string 1 m length is rotate in a verticle circle with a uniform speed of 4 m//s . The tension in the string will be 52 N, when the mass is at (g=10 m//s^(2))

A mass of 5 kg is tied to a string of length 1.0 m and is rotated in vertical circle with a uniform speed of 4m//s . The tension in the string will be 130 N when the mass is at (g= 10 m//s^2 )