In a `DeltaA B C ,tanA+tanB+tanC=6 and tan A tan B=2` then the triangle is

In DeltaABC, if tanA+tanB+tanC=6 and tanA.tanB=2 then tanC= . .

tanA +tanB + tanC = tanA tanB tanC if

tanA +tanB + tanC = tanA tanB tanC if

In a triangle, tanA + tanB + tanC = 6 and tanA tanB = 2 , then the values of tanA, tanB, tanC are :

In triangle A B C ,tanA+tanB+tanC=6a n dtanAtanB=2, then the values of tanA ,tanB ,tanC are, respectively (a)1,2,3 (b) 3,2//3,7//3 (c)4,1//2 ,3//2 (d) none of these

In triangle A B C ,tanA+tanB+tanC=6a n dtanAtanB=2, then the values of tanA ,tanB ,tanC are, respectively (a) 1,2,3 (b) 3,2//3,7//3 (c) 4,1//2 ,3//2 (d) none of these

In triangle A B C ,tanA+tanB+tanC=6a n dtanAtanB=2, then the values of tanA ,tanB ,tanC are, respectively (a) 1,2,3 (b) 3,2//3,7//3 (c) 4,1//2 ,3//2 (d) none of these

In triangle ABC, tan A + tan B + tan C = 6 and tanA tanB = 2, then the values of tan A, tan B, tan C are, respectively:

In a triangle ABC, tanA+tanB+tanC=6 and tanA. tan B = 3, then find the nature of triangle.