`(x+1)^3+(x-1)^3`

The solution of (2x+3)/(2x - 1) = (3x-1)/(3x + 1) is

Let f: RvecRf(x)=x^3-3x^2+3x-2, then f^(-1)(x) is given by 1+(x+1)^(1/3) (2) 1+(x-1)^(1/3) x+1 3-1 (4) x-1 3-1

lim_{x \to 1} (3x-1)^2/(x+1)^3

The solution of (2x+3)/(2x-1)=(3x-1)/(3x+1) is

int(x^2)/((x-1)(3x-1)(3x-2))dx=

Integrate the following w.r.t. x: int frac{x^2}{(x-1)(3x-1)(3x-2)} dx

The value of int_0^1(sqrt(x)dx)/((x+1)(3x+1)(x+3)) is

if y=1/(x^3 +1/(x^3+1/(x^3................oo)) then (dy)/(dx)