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At the instant t=0, a force F=kt (k is a...

At the instant `t=0`, a force `F=kt` (k is a constant) acts on a small body of mass m resting on a smooth horizontal surface. The time, when the body leaves the surface is

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At the moment t = 0 , the force F = kt is applied to a small body of mass 'm' resting on a smoth horizontal plane. (K is a positive constant ). The direction of the force an angle theta with the horizontal always as shown Consider the body to leave the surface at an instant t=t_0 then which of the following curves represent velocity ''V'' Vs time 't' for the motion of the body in the interval 0 lt t lt t_0

At the moment t=0 force F=kt is applied to a small body of mass m resting on a smooth horizontal plane (k is a constant) The direction of this force always forms an angle theta with the horizontal as shown. Find the time t at which moment, the body breaks off the plane:

At the moment t = 0, the foce F = kt is applied to a small body of mass 'm' resting on a smooth horizontal plane, (K is a positive constant ) . The direction of the force forms an angle theta with the horizontal always as shown which of the option (s) is /are correct ?

At the moment t = 0 , the force F = kt is applied to a small body of mass 'm' resting on a smoth horizontal plane. (K is a positive constant ). The direction of the force an angle theta with the horizontal always as shown The distance travelled x by the body along horizontal before it leaves contact with the horizontal at t =t_0 can be expressed in relation with time 't' as