The mean of five positive integers is twice their median. If four of the integers are 3, 4, 6, 9 and median is 6, then find the fifth integer.

Write any five positive integers.

The sum of first 40 positive integers divisible by 6 is

The sum of 6 integers is 45. What is the average of the 6 integers ?

If the mean of the five consecutive positive integers is 12, find the mean of the least and the highest value.

Let x_1, x_2 , .....,x_11 be 11 distinct positive integers. If we replace the largest of these integers by the median of the other 10 integers, then

The average of the 9 consecutive positive integers is 63. The product of the largest and smallest integers is