Prove: `(cos e c\ A-sinA)(secA-cosA)(tanA+cotA)=1`

(cosecA-sinA)(secA-cosA)(tanA+cotA) = __________.

Prove the following identities,where the angles involved are acute angles for which the expressions are defined. (cosec A-sinA)(secA-cosA)= (1)/(tanA+cotA)

Porve that : (cosecA-sinA)(secA-cosA) =(1)/(tanA+cotA)

Porve that : (cosecA-sinA)(secA-cosA) =(1)/(tanA+cotA)

Prove: secA(1-sinA)(secA+tanA)=1

cosA(secA-cosA)(cotA+tanA)=?

Prove the following identities,where the angles involves are acute angles for which the expressions are defined:(ix) (CosecA-SinA)(SecA-CosA)=1/(tanA+cotA)

Prove: (secA-cos e c\ A)(1+tanA+cotA)=tanAsecA-cotA cos e c\ A .

Prove that secA(1-sinA)(secA+tanA)=1