1 mol of `N_2` and 4 mol of `H_2` are allowed to react in a vessel and after reaction, `H_2O` is added. Aqueous solution required 1 mol of HCI for neutralization. Mol fraction of `H_2` in the mixture after reaction is :

1 mol of N_(2) and 4 mol of H_(2) are allowed to react in a sealed container and after the reaction some water is introduced in it. The aqueous solution formed required 1 L of 1 M HCl for neutralization. Calculate the mole fraction of the gaseous product in the mixture after the reaction.

1 mol of N_(2) and 2 mol of H_(2) are allowed to react in a 1 dm^(3) vessel. At equilibrium, 0.8 mol of NH_(3) is formed. The concentration of H_(2) in the vessel is

1 mol of N_(2) and 2 mol of H_(2) are allowed to react in a 1 dm^(3) vessel. At equilibrium, 0.8 mol of NH_(3) is formed. The concentration of H_(2) in the vessel is

Under S.T.P. 1 mol of N_(2) and 3 mol of H_(2) will form on complete reaction

A mixture of 1.57 mol of N_2 , 1.92 mol of H_2 and 8.13 mol of NH_3 is introduced into a 20L vessel at 500K. K_c for the reaction N_2+3H_2iff2NH_3 is 1.7 xx10^2 at 500K. Is the reaction mixture at equilibrium. If not, what is the direction of the net reaction.

1 mol of H_(2)O(l) is formed when 1 mol of H^(+) ions and 1 mol of OH^(-) ions react together is aqueous solution. Does this reaction represent the formation reaction of water?

A mixture of 1.57 mol of n_2 ,1.92 mol of H_2 and 8.13 mol of NH_3 is introduced into a 20 L reaction vessel at 500 kAt this temperature,the equilibrium constant. K_C for the reaction N_2(g) + 3H_2(g) hArr 2NH_3(g) is 1.7 xx 10 ^2 .Is the reaction mixture at equilibrium?If not,what is the direction of the net reaction?

At 700 K, CO_(2) and H_(2) react to form CO and H_(2)O . For this purpose, K_(c ) is 0.11 . If a mixture of 0.45 mol of CO_(2) and 0.45 mol of H_(2) is heated to 700 K . (a) Find out amount of each gas at equilibrium. (b) When equilibrium has been reached, another 0.34 mol of CO_(2) and 0.34 mol of H_(2) are added to the reaction mixture. Find the composition of of mixture at new equilibrium.

At 700 K, CO_(2) and H_(2) react to form CO and H_(2)O . For this purpose, K_(c ) is 0.11 . If a mixture of 0.45 mol of CO_(2) and 0.45 mol of H_(2) is heated to 700 K . (a) Find out amount of each gas at equilibrium. (b) When equilibrium has been reached, another 0.34 mol of CO_(2) and 0.34 mol of H_(2) are added to the reaction mixture. Find the composition of of mixture at new equilibrium.