`int(sqrt(x^2-8))/(x^4)`

int_(2)^(4) (sqrt(x^(2)-4))/(x^(4))dx=

int1/sqrt(x^2-3x+8)dx

" (i) "int sqrt(x^(2)-8)dx

int_(0)^(1)((3x^(2))/(sqrt(1-x^(6)))+(4x^(3))/(sqrt(1-x^(8)))+(5x^(4))/(sqrt(1-x^(10)))+...." to "n" terms ")dx=

int(dx)/(sqrt(x^2-8x-20))=

Evaluate: (i) int(a^x)/(sqrt(1-a^(2x)))\ dx (ii) int(2x)/(sqrt(1-x^2-x^4))\ dx

int(dx)/(sqrt(3x^2+8))=

Integrate int sqrt(x^2-8x+7) dx

int sqrt(8+2x-x^(2))dx

int sqrt(x^(2)+8x-6)dx