Prove that `2sin2^0+4sin4^0+6"sin"6^0+.......+180sin180^0=90cot1^0dot`

Prove that 2sin2^(0)+4sin4^(0)+6sin6^(0)+......+180sin180^(@)=90cot1^(0)

Prove that 2sin2^(@)+4sin4^(@)+6sin6^(@)+...+180sin180^(@)=90cot1^(@)

Prove that 2 sin 2^(@)+4sin 4^(@)+6sin 6^(@)+........+180sin 180^(@)=90 cot 1^(@) .

Prove that 2 sin 2^(@)+4sin 4^(@)+6sin 6^(@)+........+180sin 180^(@)=90 cot 10^(@) .

Prove that 2 sin 2^(@)+4sin 4^(@)+6sin 6^(@)+........+180sin 180^(@)=90 cot 10^(@) .

Prove that: sin 12^0sin 48^0sin 54^0=1/8dot

Prove that sin6^0sin42^0sin66^0sin78^0=1/(16)

Prove that: sin6^0sin42^0sin 66^0sin 78^0=1/(16)

sin2x + sin4x + sin6x=0

The average value of sin2^@,sin4^@, sin6^@.........sin180^@ is (i) 1/90 cos1^0 (ii) 1/90 sin1^0 (iii) 1/90cot1^0 (iv) none of these