What is the force exerted by a photon beam of intensity `1.4kW//m^(2)`, if it falls on a perfectly absorbing disc of radius 4 metre ?

What is the force exerted by a photon of intensity 1.4 k W m^(-2) if it falls on a perfect absorber of radius 2 m ?

What is the force exerted by a photon of intensity 1.4 k W m^(-2) if it falls on a perfect absorber of radius 2 m ?

A parallel beam of monochromatic light of frequency v is incident on a surface. Intensity of the beam is I and area of the surface is A. Find the force exerted by the light beam on the surface for following cases– (i) the surface is perfectly absorbing and the light beam is incident normally on it. (ii) the surface is perfectly reflecting and the light beam is incident normally. (iii) the surface is perfectly absorbing and the light beam is incident at an angle of incidence theta . (iv) the surface is perfectly reflecting and the light beam is incident at an angle of incidence theta .

The amplitude of electric field in a parallel light beam of intensity 4Wm^(-2) is

A plane electromagnetic wave travelling along X - direction has electric field of amplitude 300 Vm^(-1) , directed along the Y - axis (a) What is the intensity of the wave ? (b) If the wave falls on a perfectly absorbing sheet of area 3.0 m^(2) , at what rate is the momentum delivered to the sheet and what is the radiation pressure exerted on the sheet ? [epsilon_(0)=8.854xx10^(-12)C^(2)N^(-1)m^(-2), c=3xx10^(8)ms^(-1)]

" of intensity "1.5kW/m^(2)" is incident normally on a perfectly absorbing surface.The pressure exerted by the light on the surface is "n times10^(-6)Pa" .Value of "n" is "