`E_(Cu^(2+)//Cu)^(@)=0.34V`
`E_(Cu^(+)//Cu)^(@)=0.522V`
`E_(Cu^(2+)//Cu^(+))^(@)=`

E_(Cu^(2+)//Cu)^(@) =0.43V E_(Cu^(+)//Cu)^(@)=0.55V E_(Cu^(2+)//Cu^(+))^(@) =

If E_(Cu^(2+)|Cu^(+))^(@)=+0.15V and E_(Cu^(2+)|Cu)^(@) and E_(Cu^(2+)|Cu)^(@)=+0.34V at 25^(@)C, then E^(@) value of the reaction 2Cu^(+)(aq)rarr Cu^(2+)(aq)+Cu(s) is -

Find the equilibrium constant for the reaction Cu^(2+)+In^(2+)hArrCu^(+)+In^(3+) Given that E_("cu^(2+)//Cu^(+))^(@)=0.15V ,? E_(In^(2+)//In^(+))^(@)=-0.4V , E_(In^(3+)//In^(+))^(@)=-0.42V

Given the standard electrod potentials E_(Cu^(2+)//Cu)^(@)=0.34v and E_(Cu^(+)//Cu)^(@)=0.52V . What is K_(c) for the disproportion 2Cu^(+)toCu+Cu^(2+)

Given that E_(Cu^(2+)//Cu)^(0)=0.337 and E_(Cu^(+)//Cu^(2+))^(0)=-0.153V . then calculate E_(Cu^(+)//Cu)^(0)

Given that E_(Cu^(2+)//Cu)^(0)=0.337 and E_(Cu^(+)//Cu^(2+))^(0)=-0.153V . then calculate E_(Cu^(+)//Cu)^(0)

Find the equilibrium constant for the reaction: Cu^(2+)+In^(2+)hArr Cu^(+)+In^(3+) Given : E_(Cu^(2+)|Cu^(+))^(@)=0.15V, E_(In^(2+)|In^(+))^(@)=-0.4V, E_(In^(3+)|In^(+))^(@)=-0.42V

Cu^(+) ion is not stable in aqueous solution because because of dispropotionation reaction. E^(@) value of disproportionation of Cu^(+) is [E_(Cu^(2+)//Cu^(+))^(@)=+ 0.15 V, E_(Cu^(2+)//Cu)^(@)=0.34 V]