A charged cork ball of mass m = 16 g is suspended from a light string in the presence of a uniform electric field as shown in the figure. When `E=(1/2hati+2hatj)N//C` , the ball is in equiligrium at the angle of `37^@`. find W if

The charge on the ball is `Wxx10^(-2)C.`

A charged cork ball of mass m = 16 g is suspended from a light string in the presence of a uniform electric field as shown in the figure. When E=(1/2hati+2hatj)N//C , the ball is in equiligrium at the angle of 37^@ . find W if The tension in the string is Wxx10^(-2)N.

A charged cork ball of mass m is suspended on a light sting in the presence of a uniform electric field as shown in fig. When E=(A hat i+B hat j)NC^(-1) , Where A and B positive numbers, the ball is in equilibirum at theta . Find (a) the charge on the ball and (b) the tension in the string.

A charged cork ball of mass m is suspended on a light sting in the presence of a uniform electric field as shown in fig. When E=(A hat i+B hat j)NC^(-1) , Where A and B positive numbers, the ball is in equilibirum at theta . Find (a) the charge on the ball and (b) the tension in the string.

A charged cork ball having mass of 1 gram and charge q is suspended on a light string in a uniform electric field as shown in the figure. The ball is in equilibrium at 0=37^(@) , when value of electric field is vecE=(3hati+5hatj)xx10^(5)N//C . Assume T as tension in the string. Which of the following options are correct? (Given sin37^(@)=0.60andg=10m//s^(2) )

A charged ball of mass 9 kg is suspended from a string in a uniform elelctric field vecE = (3hati + 5hatj) xx 10^5 N//C . The ball is in equilibrium with theta=37^@ . If direction of electric field is reversed, find the new equilibrium position of the ball. Given your answer in terms of angle made by string with vertical. Take g = 10ms^(-2) .

A charged cork of mass m suspended by a light string is placed in uniform electric field filed of strength E = (hati+hatj) xx 10^(5)NC^(-1) as shown in the figure. If in equilibrium position tension in the string is 2mg//(1+sqrt3) the angle alpha with the vertical can be

A charges cork of mass m suspended by a light stright is placed in uniform electric field strength E=(hat(i)+hat(j))xx10^(5) NC^(-1) as shown in the figure. If in equilibrium position tension in the string is (2mg)/((1+sqrt(3))) then angle 'alpha' with the vertical is:

A charges cork of mass m suspended by a light stright is placed in uniform electric field strength E=(hat(i)+hat(j))xx10^(5) NC^(-1) as shown in the figure. If in equilibrium position tension in the string is (2mg)/((1+sqrt(3))) then angle 'alpha' with the vertical is: