I.` a^(2) + 72 = 108`
II.` b^(3) + 581 = 365`

I. x^(2) + 72 = 108" "II. Y^(2) = 6

I. x^(2) - 72 = x" " II. y^(2) = 64

I. x^(2) + 17x+72 = 0" " II. y^(2) + 19y + 90 = 0

I. x = (216)^(1//3)" "II. Y^(3) +581 = 365

(i) x^(2) -18x+72 = 0 (ii) y^(2)=36

Simplify the following by using (a+b)(a-b)=a^2-b^2dot (i) 68 xx 72 (ii) 101 xx 99 (iii) 67 xx 73 (iv) 128^2-77^2

Find the HCF of 72, 108 and 180. (A) 72 (B) 24 (C ) 12 (D) 36

Find : (a) 1/2 of (i) 24 (ii) 46 (b) 2/3 of (i) 18 (ii) 27 (c) 3/4 of (i) 16 (ii) 36 (d) 4/5 of (i) 20 (ii) 35

Divide: (i) 72 by 576 (ii) 144 by 15