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int (cos 2x-cos 2 theta)/(cos x-cos thet...

`int (cos 2x-cos 2 theta)/(cos x-cos theta)dx`

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Evaluate: int(cos2x-cos2 theta)/(cos x-cos theta)dx

int(cos 2x-cos 2 theta)/(cosx-cos theta)dx=....+C

int(cos2x-cos2 theta)/(cos x-cos theta)dx is equal to 2(sin x-cos theta)+C(b)2(sin x+x cos theta)+C(b)2(sin x-x cos theta)+C(d)2(sin x+2x cos theta)+C(d)2(sin x-2x cos theta)+C

Evaluate: int(cos2x-cos2theta)/(cosx-costheta)dx

Evaluate: int(cos2x-cos2theta)/(cosx-costheta)dx

Evaluate: int(cos2x-cos2theta)/(cosx-costheta)dx

Evaluate: int(cos2x-cos2theta)/(cosx-costheta)dx

int (cos2x - cos 2theta)/(cosx- costheta)dx is equal to

int (cos2x-cos2theta)/(cosx-costheta)dx is equal to