यदि `((2n)!)/(3!(2n-3)!)` तथा `(n!)/(2!(n-2)!), 44:3` के अनुपात में हैं, तो n का मान ज्ञात कीजिए ।

- यदि nc8 = nc2, तो n का मान ज्ञात कीजिये ?

Solve for n : ((2n)!)/( 3!( 2n-3) !) : ( n!)/( 2!( n-2)!) = 44 : 3

If ((2n)!)/(3!(2n-3)!) and (n!)/(2!(n-2)!) are in the ratio 44:3 find n.

If ((2n!))/((3!)xx(2n-3)!): (n!)/((2!)xx(n-2)!)=44:3 , find the value of n.

If ((2n)!)/(3!(2n-3)!)a n d(n !)/(2!(n-2)!) are in the ratio 44 :3, find ndot

(i) If (n!)/(2.(n-2)!): (n!)/(4!.(n-4)!) = 2:1 , find the valye of n. (ii) If ((2n)!)/(3!(2n-3)!): (n!)/(2!(n-2)!) = 44:3 , then find the value of n.

(i) If (n!)/(2.(n-2)!): (n!)/(4!.(n-4)!) = 2:1 , find the valye of n. (ii) If ((2n)!)/(3!(2n-3)!): (n!)/(2!(n-2)!) = 44:3 , then find the value of n.