`int_(0)^(1) x tan^(-1) x " "dx =`

int_(0)^(1) x^(3) tan^(-1) x " "dx =

int_0^(1) tan^(-1) x dx =

int_(0)^(1)x cos(tan^(-1)x)dx

If int_(0)^(1) tan^(-1) x dx = p , then the value of int_(0)^(1) tan^(-1)((1-x)/(1 +x)) dx is

If int_(0)^(1) tan^(-1) x dx = p , then the value of int_(0)^(1) tan^(-1)((1-x)/(1 +x)) dx is

int _(0)^(1) (tan ^(-1))/(x ) dx =

If 2 int_(0)^(1) tan^(-1) x dx = int_(0)^(1) cot^(-1) (1- x+x^(2))dx , then int_(0)^(1) tan^(-1) (1-x+x^(2))dx is equal to

int_(0)^(1)x(tan^(-1)x)^(2)dx

2 int_(0)^(1) (tan^(-1)x)/(x) dx=

int _(0)^(1) (tan ^(-1)x)/(x ) dx =