If the graph of equation `2x+ky=10k`, intersect x-axis at point `(5,0)`. Find value of k.

If the graph of equation 2x+ky =10 intersects x axis at point (5,0) find the value of k

The graphs of the linear equaton 4x-2y=10 and 4x+ky=2 intersect at a point (a,4). The value of k is equal to:

If the graphs of x^(2) = 4(y+9) and x + ky = 6 intersect on the x-axis , then k =

The graph of y = 2x^2 + 10x + 12 is shown. If the graph crosses the y -axis at the point ( 0, k) , what is the value of k ?

f(x)=3x^(3)+kx^(2)-32x+28 The function f is defined by the equation above where k is a nonzero constant. In the xy-plane the graph of f intersects the x-axis at three points: (-2, 0), ((3)/(2), 0), and (c, 0) . What is the value of k?

If the line 2x - ky + 6 = 0 passes through the point (2,-8) , then find the value of k.

If one root of the equation 2x^2-5x+k=0 be twice the other, find the value of k.

If the point (k,k^(2)) lies on the graph of the equation x+y=6, then find the value / values of k.

If the equations 4x+7y=10 and 10x+ky=25 represent coincident lines then find the value of k?

If the equations 4x+7y=10 and 10x+ky=25 represent coincident lines then find the value of k?