if `c!=0` and the equation `p/(2x)=a/(x+c)+b/(x-c)` has two equal roots, then p can be

If c ne 0 and the equation (p)/(2x)=(a)/(x+c)+(b)/(x-c) has two equal roots, then p can be

If c ne 0 and the equation (p)/(2x)=(a)/(x+c)+(b)/(x-c) has two equal roots, then p can be

If c ne 0 and p/(2x)= a/(x+c) + b/(x-c) has two equal roots, then find p.

If the quadratic equation (b-c)x_2+(c-a)x+(a-)=0 has equal roots, then show that 2b=a+c .

If the quadratic equation (b-c)x_2+(c-a)x+(a-b)=0 has equal roots, then show that 2b=a+c .

If (x)=ax^(2)+bx+c&Q(x)=-ax^(2)+dx+c,ac!=0P(x)=ax^(2)+bx+c&Q(x)=-ax^(2)+dx+c,ac!=0 then the equation P(x)*Q(x)=0 has (a) Exactly two real roots (b) Atleast two real roots (c)Exactly four real roots (d) No real roots

A quadratic trinomial P(x)=a x^2+b x+c is such that the equation P(x)=x has no real roots. Prove that in this case equation P(P(x))=x has no real roots either.

A quadratic trinomial P(x)=a x^2+b x+c is such that the equation P(x)=x has o real roots. Prove that in this case equation P(P(x))=x has no real roots either.

A quadratic trinomial P(x)=a x^2+b x+c is such that the equation P(x)=x has no real roots. Prove that in this case equation P(P(x))=x has no real roots either.

A quadratic trinomial P(x)=a x^2+b x+c is such that the equation P(x)=x has no real roots. Prove that in this case equation P(P(x))=x has no real roots either.