Let `g(x) = ln f(x)` where f(x) is a twice differentiable positive function on `(0, oo)` such that `f(x+1) = x f(x)`. Then for N = 1,2,3 `g''(N+1/2)- g''(1/2) =`

Let g(x)=ln f(x) where f(x) is a twice differentiable positive function on (0,oo) such that f(x+1)=xf(x). Then for N=1,2,3g'(N+(1)/(2))-g'((1)/(2))=

Let g(x) = log (f(x)) where f(x) is twice differentiable positive function on (0,oo) such that f(x+1)=xf(x) then for N = 1,2,3 and g''(N+1/2)-g''(1/2) = k (1+(1)/(9)+1/25+......+1/((2N-1)^2)) then 'k' is

Leg g(x)=ln(f(x)), whre f(x) is a twice differentiable positive function on (0,oo) such that f(x+1)=xf(x)dot Then, for N=1,2,3, g^(N+1/2)-g^(1/2)=

Let g(x)=log(f(x)) , where f(x) is a twice differentiable positive function on (0,oo) , such that f(x+1)=xf(x) . Then for N=1,2,3, . . .. . . .. . . g'(N+1/2)-g''((1)/(2))=

Leg g(x)=ln(f(x)), whre f(x) is a twice differentiable positive function on (0,oo) such that f(x+1)=xf(x) .Then,for N=1,2,3,......g^(n)(N+(1)/(2))-g^(n)((1)/(2))=

Let g(x)=f(x)sin x, where f(x) is a twice differentiable function on (-oo,oo) such that f(-pi)=1. The value of |g'(-pi)| equals

If f(x) and g(x) are twice differentiable functions on (0,3) satisfying f"(x) = g"(x), f'(1) = 4, g'(1)=6,f(2)=3, g(2) = 9, then f(1)-g(1) is