The boiling point elevation of 600 mg of acetic acid in 0.1 kg of benzene is 0.1265 K. What conclusion can you draw about the molecular state of acetic acid in benzene ? `K_b` of benzene is 2.53 k//m.

The freezing point depression of 0.1 molal solution of acetic acid in benzene is 0.256 K kg mol^(-1) .Kf for benzene is 5.12 K kg Mol^(-1) . What conclusion can you draw about the molecular state of acetic acid in benzene.

The freezing point depression of 0.1 molal solution of acetic acid in benzene is 0.256 K , K_(f) for benzene is 5.12 K Kg mol^(-1) . What conclusion can you draw about the molecular state of acetic acid in benzence ?

The freezing point depression of 0.1 molal solution of acetic acid in benzene is 0.256 K , K_(f) for benzene is 5.12 K Kg mol^(-1) . What conclusion can you draw about the molecular state of acetic acid in benzence ?

The freezing point depression of 0.1 molal NaCl solution is 0.372 K. What conclusion can you draw about the molecular state of NaCl in water. K_f of water = 1.86 k/m.

The freezing point depression of 0.1 molal NaCl solution is 0.372 K. What conclusion can you draw about the molecular state of NaCl in water. K_f of water = 1.86 k/m.

The elevation in boiling point when 0.30 g of acetic acid is dissolved in 100 g of benzene is 0.0633^(@)C . Calculate the molecular weight of acetic acid from this data. What conclusion can you draw about the molecular state of the solute in the solution? (Given K_(b) for benzene =2.53"K kg mol"^(-1) , at wt. of C=12, H=1, O=16)

Explain giving examples the term 'colligative molality'. Why do we sometimes get abnormal molecular masses of the substances using colligative properties of the solution? The freezing point depression of 0.1 molal solution of benzoic acid in benzene is 0.526K . For benzene K_(f) is 5.12K kg "mol"^(-1) . Calculate the value of van't Hoff factor for benzoic acid in benzene. What conclusion can you draw about the molecular state of benzoic acid in benzene?