The `n` rows each containinig `m` cells in series are joined parallel. Maximum current is taken from this combination across jan external resistance of `3 Omega` resistance. If the total number of cells used are 24 and internal resistance of each cell is `0.5 Omega` then

To get maximum current in a resistance of 3 ohm one can use n rows of m cells connected in parallel. If the total no. of cells is 24 and the internal resistance of a cell is 0.5

In a mixed grouping of identical cells, five rows are connected in parallel and each row contains 10 cells. This combination sends a current I through an external resistance of 20Omega. if the emf and internal resistance of each cell is 1.5 V and 1 Omega, respectively then find the value of I.

In a mixed grouping of identical cells, five rows are connected in parallel and each row contains 10 cells. This combination sends a current I through an external resistance of 20Omega. if the emf and internal resistance of each cell is 1.5 V and 1 Omega, respectively then find the value of I.

Two similar cells, whether joined in series or in parallel, have the same current through an external resistance of 2Omega . The internal resistance of each cell is :

The minimum number of cells in mixed grouping required to produce a maximum current of 1.5A through an external resistance of 30Omega , given the emf of each cell is 1.5 V and internal resistance is 1Omega is

To get maximum current in a resistance of 3Omega , one can use n parallel rows of m cells each (connected in series). If the total no. of cells is 24 and the internal resistance is 0.5 ohm then