The work function of nickle is `5eV`. When light of wavelength `2000A^(0)` falls on it, emits photoelectrons in the circuit. The the potential difference necessary to stop the fastest electrons emitted is (given `h=6.67xx10^(-34) Js`)

The work function of the nickel is 5 eV. When a light of wavelength 2000 Å falls on it ,it emits photoelectrons in the circuit .Then, the potential difference necessary to stop the faster electrons emitted is (Given , h=6.67xx10^(-34)J-s)

The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength 2000A falls on it. The potential difference applied to stop the fastest photoelectrons is

The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength 2000A falls on it. The potential difference applied to stop the fastest photoelectrons is

The work function of a metallic surface is 5.01 eV . The photo - electrons are emitted when light of wavelength 2000 Å falls on it . The potential difference applied to stop the fastest photo - electrons is [ h = 4.14 xx 10^(-15) eV sec]

The work function of a metallic surface is 5.01 eV . The photo - electrons are emitted when light of wavelength 2000 Å falls on it . The potential difference applied to stop the fastest photo - electrons is [ h = 4.14 xx 10^(-15) eV sec]

The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength 2000A falls on it. The potential difference applied to stop the fastes photoelectrons is [h=4.14xx10^(-15)eVs]

A radiation of wave length 2500A^(0) is incident on a metal plate whose work function is 3.5eV . Then the potential required to stop the fastest photo electrons emitted by the surface is (h=6.63xx10^(-34)Js & c=3xx10^(8)m//s)