The line `x cos alpha+ y sin alpha=p` , intersects the circle `x^2 + y^2= 4` at A and B. If the chord AB makes an angle `30^@` at a point on the circumference of the circle, then `p^2=`

If line x cos alpha + y sin alpha = p " touches circle " x^(2) + y^(2) =2ax then p =

The line x sin alpha - y cos alpha =a touches the circle x ^(2) +y ^(2) =a ^(2), then,

The line x cos alpha+y sin alpha=p touches the circle x^(2)+y^(2)-2ax cos alpha-2ay sin alpha=0. then p=

The circle on the chord x cos alpha + y sin alpha -p= 0 of the circle x^2 + y^2 - 2 = 0 as diameter is:

The circle on the chord xcos alpha + ysin alpha =p of the circle x^2+y^2=r^2 as diameter is

If the straight line represented by x cos alpha + y sin alpha = p intersect the circle x^2+y^2=a^2 at the points A and B , then show that the equation of the circle with AB as diameter is (x^2+y^2-a^2)-2p(xcos alpha+y sin alpha-p)=0

If the straight line represented by x cos alpha + y sin alpha = p intersect the circle x^2+y^2=a^2 at the points A and B , then show that the equation of the circle with AB as diameter is (x^2+y^2-a^2)-2p(xcos alpha+y sin alpha-p)=0