Two dielectric slabs of constant K1 and K2 have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor

Two dielctric slabs of constant K_(1) and K_(2) have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor ?

Two dielectric slabs of dielectric constants K_1 and K_2 are filled in between two plates each of area A, of a parallel plate capacitor. Find net capacitance.

A parallel plate capacitor consists of two identical metal plates. Two dielectric slabs having dielectric donstants k_1 and k_2 are introduced in the space between two plates as shown below. Show that capacity of capacitor in arrangement (a) is given by , C = (epsilon_0 (k_1+k_2)A)/(2d)

Two dielectric slabs of dielectric constant K_1 and K_2 are filled in between the two plates, each of area A, of the parallel plate capacitor as shown in the figure. What will be the capacitance of the capacitor

Two dielectric slabs of dielectric constants K_(1) and K_(2) are filled in between the two plates, eachof area A of the parallel plate capacitor as shown in the figure. Find the net capacitance of the capacitor.

Two material having the dielectric constans K_(1) and K_(2) are filled between two parallel plates of a capacitor. where area of each plate is A and the distance between the plates is d . The capacitor of the capacitor is:

A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant K_1 and K_2 of same area A//2 and thickness d//2 are inserted in the space between the plates. The capacitance of the capacitor will be given by :

Two thin dielectric slabs of dielectric constants K_1 and K_2 (K_1ltK_2) are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field E between the plates with distance d as measured from plate P is correctly shown by

Two identical capacitors A and B shown in the given circuit are joined in series with a battery. If a dielectric slab of dielectric constant K is slipped between the plates of capacitor B and battery remains connected, then the energy of capacitor A will-