The sum of first n, 2n and 3n terms of an A.P. are `S_(1), S_(2), S_(3)` respectively. Prove that `S_(3)=3(S_(2)-S_(1))`.

The sums of n, 2n , 3n terms of an A.P. are S_(1) , S_(2) , S_(3) respectively. Prove that : S_(3) = 3 (S_(2) - S_(1) )

Let sum of n , 2n , 3n , terms of an A.P are S_(1), S_(2), S_(3) respectively. Prove that S_(3) = 3 (S_(2) - S_(1)) .

The sum of n,2n,3n terms of an A.P.are S_(1),S_(2),S_(3) respectively.Prove that S_(3)=3(S_(2)-S_(1))

If the sum of n, 2n, 3n terms of an A.P are S_(1), S_(2), S_(3) , respectively, prove that S_(3) = 3 (S_(2) -S_(1)).

If the sum of n,2n,3n terms of an AP are S_(1),S_(2),S_(3) respectively.Prove that S_(3)=3(S_(2)-S_(1))

The sum of n,2n,3n terms of an A.P.are S_(1)S_(2),S_(3), respectively.Prove that S_(3)=3(S_(2)-S_(1))

If the sums of n, 2n and 3n terms of an A.P. be S_(1), S_(2), S_(3) respectively, then show that, S_(3) = 3(S_(2) - S_(1)) .

The sum of n, 2n, 3n terms of an A.P. are S_1, S_2, S_3 respectively. Prove that S_3 = 3(S_2 - S_1)

Let the sum of n, 2n, 3n terms of an A.P. be S_(1), S_(2) and S_(3) respectively. Show that S_(3) = 3(S_(2) - S_(1)) .