If `f:R rarr R, g:R rarr R` are defined by `f(x)=4x-1, g(x)=x^(3)+2,` then `(gof)((a+1)/(4))=`

If f:R rarr R, g:R rarr R are defined by f(x)= 5x-3,g(x)=x^(2)+3 , then (gof^(-1))(3)=

If f:R rarr R, g:R rarr R are defined by f(x)=x^(2)+2x-3, g(x)=3x-4 , then (fog)(-1)=

If f:R rarr R,g:R rarr R are defined by f(x)=3x-4 and g(x)=2+3x ,then (g^(-1) of^(-1))(5)=

If f:R rarr R and g:R rarr R are define by f(x)=3x-4 and g(x)=2+3x , then (g^(-1)of^(-1))(5)=

If f:R rarr R, S: R rarr R are defined by f(x) = 3x-4, g(x) = 5x-1 then, (fog^(-1))(2) =

If f:R rarr and g:R rarr R are defined by f(x)=3x-4 and g(x)=2+3x then (g^(-1)" of"^(-1))(5)=

If f:R rarr R and g:R rarr R are defined by f(x)=x-[x] and g(x)=[x] is x in R then f{g(x)}

If f : R to R , g : R to R are defined by f (x) = 4x - 1 and g (x) = x ^(2) + 2 then find (gof) ((a+1)/(4))