In 5.00 s, a 2.00 kg stone moves in a horizontal circle of radius 2.00 m from rest to an angular speed of 4.00 rev/s. What are the stone's (a) average angular acceleration and (b) rotational inertia around the circle's center?

Explanation

To solve the problem step by step, we will break it down into two parts: calculating the average angular acceleration and then calculating the rotational inertia.

### Given Data:
- Mass of the stone, \( m = 2.00 \, \text{kg} \)
- Radius of the circle, \( r = 2.00 \, \text{m} \)
- Time taken, \( t = 5.00 \, \text{s} \)
- Final angular speed, \( \omega = 4.00 \, \text{rev/s} \)

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