An object rotates about a fixed axis, and the angular position of a reference line on the object is given by `theta=0.40e^(2t)`, where `theta` is in radians and t is in seconds. Consider a point on the object that is 6.0 cm from the axis of rotation. At t = 0, what are the magnitudes of the point's (a) tangential component of acceleration and (b) radial component of acceleration?

Explanation

To solve the problem, we need to find the tangential and radial components of acceleration for a point on an object rotating about a fixed axis, given the angular position as a function of time.

### Step-by-Step Solution

1. **Identify the given parameters:**
- Angular position: \(\theta(t) = 0.40 e^{2t}\) (in radians)
- Distance from the axis of rotation: \(r = 6.0 \, \text{cm} = 0.06 \, \text{m}\)
- Time: \(t = 0 \, \text{s}\)
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