A 0.50 kg meter stick can rotate around an axis perpendicular to the stick. Find the difference in the stick's rotational inertia about the rotation axis if that axis is initially at the point marked "40cm" and then at the point marked "10cm".

Explanation

To solve the problem of finding the difference in the rotational inertia of a 0.50 kg meter stick about two different axes (one at 40 cm and the other at 10 cm), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Mass per Unit Length**:
The total mass of the meter stick is 0.50 kg, and its length is 1 meter (100 cm). Therefore, the mass per unit length (λ) can be calculated as:
\[
\lambda = \frac{0.50 \, \text{kg}}{100 \, \text{cm}} = 0.005 \, \text{kg/cm}
...