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A 60 kg father and 20 kg child sit on op...

A 60 kg father and 20 kg child sit on opposite ends of a seesaw consisting of a board of length 4.0 m and negligible mass. The pivot can be placed anywhere between the father and the child. At what distance from the child should it be placed so that the seesaw is balanced when the father and child are stationary?

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To solve the problem of balancing the seesaw with a 60 kg father and a 20 kg child, we can follow these steps: ### Step 1: Understand the System We have a seesaw of length 4.0 m with a father (60 kg) on one end and a child (20 kg) on the other end. We need to find the position of the pivot (fulcrum) such that the seesaw is balanced. ### Step 2: Define Variables Let: - \( x \) = distance from the child to the pivot ...
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RESNICK AND HALLIDAY-RIGID BODY DYNAMICS - I-PROBLEMS
  1. Four identical particles of mass 0.75 kg each are placed at the vertic...

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  2. The body shown in Fig. is pivoted at point O. Three forces act on it F...

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  3. A 60 kg father and 20 kg child sit on opposite ends of a seesaw consis...

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  8. In Fig. 10-65, a cylinder having a mass of 3.0 kg can rotate about its...

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  9. Figure shows a uniform disk that can rotate around its center like a m...

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  10. In a judo foot-sweep move, you sweep your opponent's left foot out fro...

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  11. Figure shows particles 1 and 2, each of mass m, fixed to the ends of a...

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  12. A pulley, with a rotational inertia of 1.0xx10^(-3)kg*m^(2) about its ...

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