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A force vecF=(6.00hati-4.00hatj)N acts o...

A force `vecF=(6.00hati-4.00hatj)N` acts on a particle with position vector `vecr=(-3.00hati+1.00hatj)m`. Find (a) the torque about the origin acting on the particle and (b) the angle between `vecrandvecF`.

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To solve the given problem step by step, we will tackle both parts (a) and (b) systematically. ### Given: - Force vector: \(\vec{F} = (6.00 \hat{i} - 4.00 \hat{j}) \, \text{N}\) - Position vector: \(\vec{r} = (-3.00 \hat{i} + 1.00 \hat{j}) \, \text{m}\) ### Part (a): Calculate the Torque about the Origin ...
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