At the instant of Figure, a 2.0 kg particle P has a position vector `vecr` of magnitude 5.0 m and angle `theta_(1)=45^(@)` and a velocity vector `vecv` of magnitude 4.0 m/s and angle `theta_(2)=30^(@)`, Force `vecF`, of magnitude 2.0 N and angle `theta_(3)=30^(@)`, acts on P. All three vectors lie in the xy plane. About the origin, what are the (a) magnitude and (b) direction of the angular momentum of P and the ( c) magnitude and (d) direction of the torque acting on P?

Explanation

(a) `20kg*m^(2)//s`, (b) Using the right-hand rule for vector products, we find `vecrxxvecp` point out of the page, or along the +z axis, perpendicular to the plane of the figure, ( c) `5.0N*m`, (d) Using the right-hand rule for vector products, we find `rxxvecF` is also out of the page, or along the +z axis, perpendicular to the plane of the figure.