At the instant the displacement of a 1.50 kg object relative to the origin is `vecd=(2.00m)hati+(4.00m)hatj-(3.00m//s)hatk`, its velocity is `vecv=-(6.00m//s)hati+(3.00m//s)hatj+(3.00m)hatk` and it is subject to a force `vecF=(6.00N)hati-(8.00N)hatj+(4.00N)hatk`. Find (a) the acceleration of the object, (b) the angular momentum of the object about the origin, ( c) the torque about the origin acting on the object, and (d) the angle between the velocity of the object and the force acting on the object.

Explanation

(a) `(4.00m//s^(2))hati-(5.33m//s^(2))hatj+(2.67m//s^(2))hatk`, (b) `(31.5kg*m^(2)//s)hati+(18.0kg*m^(2)//s)hatj+(45.0kg*m^(2)//s)hatk`, ( c) `(-8.00N*m)hati-(26.0N*m)hatj-(40.0N*m)hatk`, (d) `127^(@)`