A sanding disk with rotational inertia `8.6xx10^(-3)kg*m^(2)` is attached to an electric drill whose motor delivers a torque of magnitude `16N*m` about the central axis of the initially stationary disk. About that axis and with the torque applied for 33 ms, what is the magnitude of the (a) angular momentum and (b) angular velocity of the disk?

Explanation

To solve the problem step by step, we will break it down into two parts: (a) finding the angular momentum and (b) finding the angular velocity of the disk.

### Given Data:
- Rotational inertia (I) = \(8.6 \times 10^{-3} \, \text{kg} \cdot \text{m}^2\)
- Torque (\(\tau\)) = \(16 \, \text{N} \cdot \text{m}\)
- Time (\(\Delta t\)) = \(33 \, \text{ms} = 33 \times 10^{-3} \, \text{s}\)

### Part (a): Finding Angular Momentum
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