A top spins at 25 rev/s about an axis that makes an angle of `30^(@)` with the vertical. The mass of the top is 0.50 kg, its rotational inertia about its central axis is `5.0xx10^(-4)kg*m^(2)`, and its center of mass is 4.2 cm from the pivot point. If the spin is clockwise from an overhead view, what are the (a) precession rate and (b) direction of the precession as viewed from overhead?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify the given values
- Mass of the top, \( m = 0.50 \, \text{kg} \)
- Gravitational acceleration, \( g = 9.81 \, \text{m/s}^2 \)
- Distance from pivot point to center of mass, \( r = 4.2 \, \text{cm} = 0.042 \, \text{m} \)
- Rotational inertia, \( I = 5.0 \times 10^{-4} \, \text{kg} \cdot \text{m}^2 \)
- Spin rate, \( \text{spin} = 25 \, \text{rev/s} \)
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