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The Earth takes slightly less than one d...

The Earth takes slightly less than one day to complete one rotation about the axis passing through its poles. The actual time is `8.616xx10^(4)`s. With this given information, what is the angular speed of the Earth about its axis?

A

`7.292xx10^(-5)` rad/s

B

`9.951xx10^(-5)` rad/s

C

`2.321xx10^(-6)` rad/s

D

`6.334xx10^(-4)` rad/s

Text Solution

AI Generated Solution

The correct Answer is:
To find the angular speed of the Earth about its axis, we can follow these steps: ### Step 1: Understand the relationship between angular speed and time period The angular speed (ω) of an object in circular motion is given by the formula: \[ \omega = \frac{2\pi}{T} \] where \(T\) is the time period for one complete rotation. ### Step 2: Identify the time period From the problem statement, the time period \(T\) for one complete rotation of the Earth is given as: \[ T = 8.616 \times 10^4 \text{ seconds} \] ### Step 3: Substitute the time period into the angular speed formula Now, we can substitute the value of \(T\) into the formula for angular speed: \[ \omega = \frac{2\pi}{8.616 \times 10^4} \] ### Step 4: Calculate the angular speed First, we calculate \(2\pi\): \[ 2\pi \approx 6.2832 \] Now, substituting this value into the equation: \[ \omega = \frac{6.2832}{8.616 \times 10^4} \] ### Step 5: Perform the division Calculating the division: \[ \omega \approx \frac{6.2832}{86160} \approx 0.0000728 \text{ radians/second} \] ### Step 6: Express the result in scientific notation To express \(0.0000728\) in scientific notation: \[ \omega \approx 7.28 \times 10^{-5} \text{ radians/second} \] ### Final Result Thus, the angular speed of the Earth about its axis is: \[ \omega \approx 7.28 \times 10^{-5} \text{ radians/second} \] ---
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