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During the spin-dry cycle of a washing m...

During the spin-dry cycle of a washing machine, the motor slows from 95 rad/s to 30 rad/s while the turning the drum through an angle of 402 rad. What is the magnitude of the angular acceleration of the motor?

A

`64rad//s^(2)`

B

`10rad//s^(2)`

C

`32rad//s^(2)`

D

`20rad//s^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the magnitude of the angular acceleration of the motor, we can use the following kinematic equation for rotational motion: \[ \omega_f^2 = \omega_i^2 + 2\alpha \theta \] Where: - \(\omega_f\) = final angular velocity (30 rad/s) - \(\omega_i\) = initial angular velocity (95 rad/s) - \(\alpha\) = angular acceleration (unknown) - \(\theta\) = angular displacement (402 rad) ### Step 1: Write down the known values - \(\omega_i = 95 \, \text{rad/s}\) - \(\omega_f = 30 \, \text{rad/s}\) - \(\theta = 402 \, \text{rad}\) ### Step 2: Substitute the known values into the equation We can rearrange the equation to solve for \(\alpha\): \[ \omega_f^2 - \omega_i^2 = 2\alpha \theta \] Substituting the known values: \[ (30)^2 - (95)^2 = 2\alpha (402) \] ### Step 3: Calculate \(\omega_f^2\) and \(\omega_i^2\) Calculating the squares: \[ 900 - 9025 = 2\alpha (402) \] ### Step 4: Simplify the equation \[ -8125 = 804\alpha \] ### Step 5: Solve for \(\alpha\) Now, divide both sides by \(804\): \[ \alpha = \frac{-8125}{804} \] Calculating this gives: \[ \alpha \approx -10.10 \, \text{rad/s}^2 \] ### Step 6: Find the magnitude of angular acceleration Since we are interested in the magnitude, we take the absolute value: \[ |\alpha| \approx 10.10 \, \text{rad/s}^2 \] ### Final Answer The magnitude of the angular acceleration of the motor is approximately \(10.10 \, \text{rad/s}^2\). ---
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