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Moment of inertia of a half ring of mass...

Moment of inertia of a half ring of mass `m` and radius `R` about an axis passing through point `A` perpendicular to the plane of the paper is `I_(A)`. If `I_(C )` is the moment of inertia of the ring about an axis perpendicular to the plane of paper and passing through point `C`, then

A

`3/2MR^(2)`

B

`2MR^(2)`

C

`2MR^(2)(1-2/pi)`

D

`2MR^(2)(1+2/pi)`

Text Solution

Verified by Experts

The correct Answer is:
C
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