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Four solid sphereas each of diameter sqr...

Four solid sphereas each of diameter `sqrt(5) cm` and mass `0.5 kg` are placed with their centres at the corners of a square of side `4 cm`. The moment of inertia of the system about the diagonal of the square is `N xx 10^(-4) kg-m^(2)`, the `N` is -

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Four solid spheres each of diameter sqart5 cm and mass 0.5 kg are placed with their centers at the corners of a square of side 4cm. The moment is Nxx10^(-4)kg - m^2 , then N is .

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Knowledge Check

  • Four spheres of diameter 2a and mass M are placed with their centres on the four corners of a square of side b. Then moment of inertia of the system about an axis about one of the sides of the square is :-

    A
    `Ma^(2)+2Mb^(2)`
    B
    `Ma^(2)`
    C
    `Ma^(2)+4Mb^(2)`
    D
    `(8)/(5)Ma^(2)+2Mb^(2)`
  • Four spheres of diameter 2a and mass M are placed with their centres on the four corners of a square of side b. Then the moment of inertia of the system about an axis along one of the sides of the square is

    A
    `(4)/(5) Ma^(2) + 2 Mb^(2)`
    B
    `(8)/(5) Ma^(2) + 2 Mb^(2)`
    C
    `(8)/(5) Ma^2 + Mb^2`
    D
    `(4)/(5) Ma^(2) + 4 Mb^(2)`
  • Four spheres each having mass m and radius r are placed with their centres on the four comers of a square of side a. Then the moment of inertia of the system about an axis along one of the sides of the square, is

    A
    `8/5mr^(2)`
    B
    `8/5mr^(2)+2ma^(2)`
    C
    `4/5mr^(2)+2ma^(2)`
    D
    `4/5mr^(2)+4ma^(2)`
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