sin x=-(sqrt(3))/(2)" का हल जात कीजए। "

2sin3x=sqrt(3)

2sin3x=sqrt(3)

If x in[(sqrt(3))/(2), 1] then [sin^(-1){(x)/(sqrt(2))+(sqrt(1-x^(2)))/(sqrt(2))}-sin^(-1)x]=

y=sin^(-1)(3sin x-4sin^(3)x)" ,then "(dy)/(dx) at x= (sqrt(3))/(2) is

Solve |sin3x+sin x|+|sin3x-sin x|=sqrt(3),-(pi)/(2)

f(x)=x^(2)-2sqrt(sin*sqrt(3)-sin sqrt(2))x-(cos sqrt(3)-cos sqrt(2))

Find the value of x in [-pi,pi] for which f(x)=sqrt(log_(2)(4sin^(2)x-2sqrt(3)sin x-2sin x+sqrt(3)+1)) is defined.

If 4sin^(2)x-2 (1+sqrt(3))sin x + sqrt(3)=0 then theta =