If `tan (alpha-beta)=(sin 2beta)/(3-cos 2beta)`, then

If tan(alpha-beta)=(sin 2beta)/(3-cos2beta) , then

If tan(alpha-beta)=(sin2 beta)/(3-cos2 beta), then ( i )tan(alpha)=2tan(beta)( ii) (1)/(2)tan(alpha)=tan(beta)( (ii) 2tan(alpha)=3tan(beta)( iv) 3tan(alpha)=2tan(beta)

If tan(alpha-beta)=(sin2beta,)/(3-cos2beta) then (a) tanalpha=2tanbeta (b) tanbeta=2tanalpha (c) 2tanalpha=3tanbeta (d) 3tanalpha=2tanbeta

If tan(alpha-beta)=(sin2beta,)/(3-cos2beta) then (a) tanalpha=2tanbeta (b) tanbeta=2tanalpha (c) 2tanalpha=3tanbeta (d) 3tanalpha=2tanbeta

If tan(alpha-beta)=(sin2beta,)/(3-cos2beta) then (a) tanalpha=2tanbeta (b) tanbeta=2tanalpha (c) 2tanalpha=3tanbeta (d) 3tanalpha=2tanbeta

If tan(alpha-beta)=(sin2 beta)/(3-cos2 beta) then (a) tan alpha=2tan beta(b)tan beta=2tan alpha(c)2tan alpha=3tan beta(d)3tan alpha=2tan beta

If tan (alpha- beta)= (sin 2 beta)/(5-cos 2 beta) , find tan alpha: tan beta .

If tan ( alpha-beta) = (sin 2 beta)/(5-cos 2 beta),"find the value of " tan alpha : tan beta.

If tan beta = 3 tan alpha, prove that tan (alpha + beta) = (2sin 2beta)/(1+cos 2beta)

If 2tan alpha=3tan beta, prove that tan(alpha-beta)=(sin2 beta)/(5-cos2 beta)