^(@)F=(9)/(5)(^(@)C)+32

The function f which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by f (c )= (9c)/(5) + 32 . Find the image of 40 and preimage of 122.

A function F(c) is defined as : F(c) =(9)/(5)*c+32. Evaluate each of the following: (i) F(0) (ii) F(28) (iii) f(-10) (iv) Value of c when F(c)=212

The function 't' which maps temperature in 'C' to 'F' is defined by t © =F When F = (9)/( 5) © + 32 then the value of C then t( C) =230

Express the following product in exponential form. a. (-5)^(14)xx(-7)^(14) b. (a)^(19)xx(-b)^(19) c. (3)^(21)xx5^(21) d. (6)^(9)xx(5)^(9) e. (x)^(13)xx(-y)^(13) f. (-7)^(32)xx(-9)^(32)

(x+5)(x+9)+(128)/(32)

Let (C)/(5)=(F-32)/(9) If C lies between 10 and 20 then :

Let A,B,C be angles of A B C and /_D=(5pi+A)/(32),/_E=(5pi+B)/(32)&/_F=(5pi+C)/(32), then (where D ,E ,F!=(npi)/2&n in I)

If t(C)=(9C)/5+32 write the value of t(28)