The velocity `v` of a point moving along a line when it is at a distance `x` from the origin is given by `a+bv^2=x^2`. Acceleration of the point at `t` is

The velocity v of a particle moving along a straight line when at a distance x from the origin is given by a + bv^(2) = x^(2) where a and b are constants then the acceleration is:

The speed v of a particle moving along a straight line, when it is at a distance (x) from a fixed point of the line is given by v^2=108-9x^2 (all equation are in CGS units):

The speed v of a particle moving along a straight line, when it is at a distance (x) from a fixed point of the line is given by v^2=108-9x^2 (all equation are in CGS units):

The speed v of particle moving along a straight line, when it is at a distance x from a fixed point on the line is given by v^2= 108 x - 9x^2 . Then magnitude of its acceleration when it is a distance 3 metre from the fixed point is

The speed v of a particle moving along a straight line. When it is at distance x from a fixed point on the line is v^(2)=144-9x^(2) . Select the correct alternatives

The speed v of a particle moving along a straight line. When it is at distance x from a fixed point on the line is v^(2)=144-9x^(2) . Select the correct alternatives

The speed v of a particle moving along a straight line. When it is at distance x from a fixed point on the line is v^(2)=144-9x^(2) . Select the correct alternatives