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Given that a alpha^2 + 2balpha + c != ...

Given that `a alpha^2 + 2balpha + c != 0` and that the system of equations `(a alpha+b)x+alphay + bz = 0 , (balpha+c)x+by + cz = 0 ,(a alpha+b)y + (balpha + c) z = 0` has a non trivial solution, then a, b,c are in

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