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Calculate the internal resistance of the...

Calculate the internal resistance of the given cell using the following data. Balancing length for in open circuit `= l _(1) = 0.60m`

Text Solution

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`r = R [ (l _(1))/(l _(2)) -1 ]`
Trial `(i) r = R [ (l _(1))/( l _(2)) -1 ] =3 (0.6)/(0.4) -1] =1.5 Omega`
Trial (ii) `r = R [ ((l _(1))/( l _(2))-1] =4 [ (0.6)/(0.44)-1] =1.45 Omega`
Trial (iii) `r = R [ (l _(1))/( l _(2)) -1 ] =5 [ (0.6)/(0.46) -1] = 1.52 Omega`
Result : Internal resistance of the given cell lies between `1.45 and 1.52 Omega`
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