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Two cells of emf 2V and 4V and internal ...

Two cells of emf 2V and 4V and internal resistance `1Omega` and `2Omega` respectively are connected in parallel so as to send the current in the same direction through an external resistance of `10Omega`. Find the potential difference across `10Omega` resistor.

Text Solution

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Applying K.V.L. to ABEFA
`10 ( I _(1) +I _(2)) + I _(1) =2`
`implies 111_(1) + 10I _(2) =2" "…(i)`
Applying K.V.L. to BCDEB
`10 ( I _(1) + I_(2)) + 2I _(2) =4`
`5I_(1) + 6I _(2) =2 " "...(ii)`
Solving (i) and (ii)
`I _(1) =- 0.5 A and `
`I _(2) = 3/4 A = 0.75`
Potential drop across `10 Omega` is
`V = ( I _(1) + I _(2)) R = 0.25 xx 10`
`= 2. 5 V`
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Knowledge Check

  • Two cells having e.m.f. 4V, 2V and internal resistances 1Omega, 1Omega are connected as shown in figure. Current through 6Omega resistance is :

    A
    1/3 A
    B
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    B
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    C
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    D
    None of the above.

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    A
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    B
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    C
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    D
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